Java program to perform binary search

import java.util.Scanner; 
class BinarySearch 
{
  public static void main(String args[])
  {
    int c, first, last, middle, n, search, array[]; 
    Scanner in = new Scanner(System.in);
    System.out.println("Enter number of elements");
    n = in.nextInt(); 
    array = new int[n]; 
    System.out.println("Enter " + n + " integers"); 
    for (c = 0; c < n; c++)
      array[c] = in.nextInt(); 
    System.out.println("Enter value to find");
    search = in.nextInt(); 
    first  = 0;
    last   = n - 1;
    middle = (first + last)/2; 
    while( first <= last )
    {
      if ( array[middle] < search )
        first = middle + 1;    
      else if ( array[middle] == search ) 
      {
        System.out.println(search + " found at location " + (middle + 1) + ".");
        break;
      }
      else
         last = middle - 1; 
      middle = (first + last)/2;
   }
   if ( first > last )
      System.out.println(search + " isn't present in the list.");
  }
}

Output

Enter number of elements
5
Enter 5 integers
2
3
5
9
10
Enter value to find
5
search found at location 3
 

Explanation

Input numbers must be in ascending order.Here we have perform the binary search